If it's not what You are looking for type in the equation solver your own equation and let us solve it.
y^2=1/3
We move all terms to the left:
y^2-(1/3)=0
We add all the numbers together, and all the variables
y^2-(+1/3)=0
We get rid of parentheses
y^2-1/3=0
We multiply all the terms by the denominator
y^2*3-1=0
Wy multiply elements
3y^2-1=0
a = 3; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·3·(-1)
Δ = 12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12}=\sqrt{4*3}=\sqrt{4}*\sqrt{3}=2\sqrt{3}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{3}}{2*3}=\frac{0-2\sqrt{3}}{6} =-\frac{2\sqrt{3}}{6} =-\frac{\sqrt{3}}{3} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{3}}{2*3}=\frac{0+2\sqrt{3}}{6} =\frac{2\sqrt{3}}{6} =\frac{\sqrt{3}}{3} $
| x=2x−4 | | -1+3y^2=0 | | 3x+3=7x-11 | | 3y^2=1 | | (2)98-6x=x+49 | | 35+90+m∠1=180 | | 40(x)+5(1.5x)=100 | | 98-6x=x+49 | | 10x-9=2x+9 | | 40x+5(1.5x)=100 | | -8+2(9x+5)=-9-9(2x-5) | | 5x+7-3x+1=12 | | 3=3(y-4) | | -2-3x+8x=18 | | -3=r-2r | | -10=-m+3m | | -30=2u=4u | | 4+5-b=-5 | | 4(5x-4)=64 | | 15y+4=94 | | 300+25x=50x | | 0=14-4y | | 7x-8+76=189 | | 15=-5z+2z | | 38=20-x | | 4x-12+2x+8=-15 | | 60/(2-x)=3 | | 5(2x-5)-3=5(x-3)+12 | | (4x+3)(8−3x)=−2x(6x−2) | | 6y-42=8 | | 15+3y^2=0 | | x-80=2x-90 |